Amphetamine Quantitative Test

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Determination of Amphetamine Purity at Home Conditions​

Introduction

The determination method of the real amount of amphetamine in a sample at home conditions without expensive or rare equipment is shown in this article. Moreover, the step by step manual of the titrimetric method are minutely represented with full explanation.

You need:
  • Sodium nitrite (NaNO2);
  • 10% Hydrochloric acid (HCl);
  • Distilled water;
  • Indicators: tropaeolin OO and methylene blue.
Equipment:
  • Vial or flask 10 ml;
  • Bakers 200 ml x2;
  • Measuring graduated pipette 0.001 ml;
  • Scales.
If you have not got opportunities to buy analytical scales, you can replace it by pharmacy scales with a set of weights. It is cheaper than the analytical one and gives quite accurate results. At the opposite side, you cannot replace the graduated pipette by syringe. Cheap, inaccurate equipment would not let you get precise results. Glassware should be perfectly clean, so you need to rinse it 3-4 times by acetone and keep it under lint-free napkin.

Titrant preparation (0,1M sodium nitrite solution).
Put 0.73 g (94.51% purity) of sodium nitrite into a measuring glass and add distilled water up to 100 ml (the accuracy is very important). You will get 100 ml of 0.1M solution of sodium nitrite.

Sample preparation.
Put the accurate weights of 10 mg of the sample into the vial, add 1 ml of distilled water and 1 ml of 10% of hydrochloric acid. Add distilled water to get the total volume of solution of 5 ml. Then add 2 drops of tropaeolin OO and 2 drops of methylene blue.
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Fill the pipette with solution of sodium nitrite. Drop in sodium nitrite solution into sample solution, one by one, until the sample solution change the color (the blue color would be occurred). After that, mention the volume of sodium solution, that was used for titration.
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For example, we add 0.2 ml for titration. We know that 100 ml of solution contain 0.69 g of pure sodium nitrite. Hence, 0.2 ml of solution contain 0,00146 g (94.51% purity) of sodium nitrite or 0.0013798 g (100% pure). The molar mass of sodium nitrite equivalent is 68.995 g/eq, the molar mass of amphetamine sulfate is 184.25 g/eq. It is possible to calculate the mass of amphetamine sulphate in investigated sample: (0.0013798/68.995)*184.25=0,00368 g or 3.68 mg. The sample weight was 10 mg; hence, the sample contain 36.8% of pure amphetamine.

This method could be applied to analysis of any other amines (all amphetamines and cathinones). This method has one disadvantage. If the sample contain any other amine, its amount would be included in the result. It means that you cannot calculate the amount of amine you are interested in. That is why it is recommended to carry out the qualitative reactions preliminary.
 
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GinaCollada

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Labai ačiū!!

Turiu vieną klausimą, ar tai tinka ir skystai amfetamino bazei?

Ačiū
 

G.Patton

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Sveiki, ne, taip nebus. Amfibazė netirpsta vandenyje pirmuoju žingsniu.
 
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Forgotten

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Ar galite naudoti 1 g amfetamino vietoj 10 g? Ir ką man reikia pakeisti ?
 

G.Patton

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Atsiprašome. Tai klaida. Jums reikia paimti 10 mg mėginį. Aš ją ištaisiau.
 

diogenes

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Sveiki, ar teoriškai galima naudoti kitus rodiklius? Pvz. tropaeolin OO mano šalyje nėra per daug prieinamas, bet gal tiesiog ieškojau ne ten, kur reikia.
 

G.Patton

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Galbūt, jei rasite ką nors naujo, galėsite tai išmokti ir pasakyti čia.
 

ACAB

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Ar galėtumėte man paaiškinti, kas yra kiekybinė reakcija ir kaip ją atlikti?
 

G.Patton

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Reakcijos, patvirtinančios amfetamino buvimą
http://bbzzzsvqcrqtki6umym6itiixfhni37ybtt7mkbjyxn2pgllzxf2qgyd.onion/index.php?threads/amphetamine-assessment-protocol.349/
 

ACAB

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Gerai, ačiū, esu su tuo susipažinęs, taip pat esu susipažinęs su TLC analize, tačiau norint pateikti kiekybinius teiginius, reikia etaloninio mėginio. Procentinei daliai nustatyti, žinoma, geriausiai tiktų titravimas su masės dalies nustatymu.

Po tam tikrų paieškų radau du mums reikalingus indikatorius, tačiau atrodo, kad tai yra kieta medžiaga arba milteliai, o čia kalbama apie lašus. Ar galiu pats pasigaminti indikatorių tirpalus, jei taip, kokį tirpiklį turėčiau naudoti, jei ne, į ką turiu atkreipti dėmesį, iš ko susideda tirpalai?
 

G.Patton

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Atsiprašau, turiu omenyje kokybinę analizę. Ištaisyta.
 

G.Patton

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http://bbzzzsvqcrqtki6umym6itiixfhni37ybtt7mkbjyxn2pgllzxf2qgyd.onion/index.php?threads/synthesis-of-materials-for-testing-pas.7/
 

ACAB

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Atsiprašau, nesusipratimas, turėjau omenyje indikatorius: tropaeolin OO ir metileno mėlynąjį, radau juos tik kaip kietąsias medžiagas :D

Kitų indikatorių tirpalų kol kas ten turiu.
 

G.Patton

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Į dvi stiklines paimta 100 mg indikatorių ir užpilta 100 ml distiliuoto vandens.
Rj4BfV0KbI
40pfq7asJC
Ip6y8bYO2W
 

ACAB

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Puikiai, ačiū. Kartais paprasčiausi sprendimai taip pat yra geriausi :D
 

Forgotten

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Ei. įpylus tropeolino gaunu violetinę spalvą. Ar mano hci per stiprus? Aš jį pagaminau iš 30,%. 30 ml 30 hci ir 70 ml vandens. Tuomet turėtų būti 10 %?
 

G.Patton

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Sveiki. Jei paėmėte 30 ml 30 % HCl aq tirpalo ir į jį įpylėte 70 ml vandens, gavote 10 %. Tai teisinga.
Ar kalbate apie šį žingsnį?
 

Forgotten

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Taip, kad žingsnis į žingsnį. O kai įlašinu o,5 ml natrio nitrito, jis tampa mėlynas. Tai yra, kai neturiu jokio amfetamino į. O kai įdedu amfetamino, jokio skirtumo nėra. Aš kažką darau ne taip, bet nežinau ką. Ar turite kokių nors patarimų, ką darau ne taip?
 

G.Patton

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Ar teisingai pagamino natrio nitritą sln, kaip čia aprašyta?
 
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