Methamphetamine synthesis from Ephedrine or Pseudoephedrine

tankikan

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How about the one-pot method? That seems the easiest way to do since we just need to mix the pseudoeffedrine, ammonium nitrate, ether, lithium metal, sodium hydroxide and some water all at once in a bottle and shake it until at certain point where we will then filter out the top layer and finally using hcl acid gas to 'salt out' (as in the video terms) the meth. But i'm not sure about the quality. And perhaps the downside of this process is it can be very hazardly dangerous during the shake process since it involved deadly reduction in the bottle. I has started to make the list from the item i mentioned above, perhaps by next week i should received all ingredients. But still looking forward for any advise since this is not my line of work. Please correct me should there is any missing ingredient.

Sorry as I'm not typing into the details for each step. But willing to share if anyone interested in it.

Cheers.
 

waltjr5858

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Empty out a good solid fire extinguisher with threads that let you unscrew the top... empty it clean it and you got a great reaction vessel thats safe and can take pressure. You can let pressure out through the trigger if needed
 
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what are the measurements for 5 grams worth for meth
 

PseudoMicroGravity

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You mean the ammount of precursors needed? I always used a 1 - 1 - 1/3 ratio. So if you were going to make 10 grams for ease of math, it would take 10 grams Pseudo, 10 grams Iodine, and 3.3 grams Red P. Then for your specific question, it would take 5g Pseudo, 5g Io, and 1.61g Red as a catalyst. If that is I did that quick dirty math in Mt head right! lol
 

waltjr5858

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What about the amount of water....important especially if they are going for a 24 hour reflux. Too much water dilutes the HI formed and it won't do squat
 

signalbrow

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handle

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AKINCI

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I succeeded in this matter a long time ago, thank you for your interest.
 

@speedboysss

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Why do I only produce this and when it is burned in a pipe it turns black unlike the meth I know
 

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darthseres

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A simple technical/theoretical question... The reaction is an oxidation/reduction... Considering that the main elements are Iodine, Phosphorus and Ephedrine... what exactly is the precise role of each element? Which one is oxidized? Which one is reduced? And the third?... I'm a new student, forgive my ignorance
 

rhinoceros

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Hello

I want to buy pharmaceutcal (Sudafed) and extract ephedrine to make philopon. I don't even know how to extract ephedrine from pharmaceutcal (Sudafed). I would really appreciate it if you could explain it in detail since I'm a beginner. I would like a detailed explanation so that I can get the finished product from the beginning.

I hope you stay healthy and have a great day today.
 

SoldadoDeDrogas

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@darthseres
Ephedrine/Pseudo is being reduced into methamphetamine (Philopon?)
Iodine is oxidized or hydrolyzed into HI, which does the reducing.
Red P is the catalyst.
I'm also not a chemist so I could be wrong.

@rhinoceros All you have to do is spend time looking and studying the forum. It is all here. Many of us have figured it out without any knowledge or experience in a small amount of time with the resources at this site. If you dig in and show that you are trying instead of asking for someone to do it for you, people will try to help if you need it. We're not gonna repeat what is already here..
 

darthseres

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Iodine is Oxidized ? Are you sure ? For what I know Oxidation means that the element lose an electron ... And in this case Iodine forms a polar covalent bond with hydrogen(and iodine is more elctronegative so almost gain an elctrone from Hydrogen) in the formation of HI ...
 

SoldadoDeDrogas

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As I said, I'm not a chemist, so no, I am only guessing.
According to one definition; Oxidation has to do with the addition of oxygen or any electronegative elements or the removal of hydrogen or any electropositive element. I was really leaning more towards the latter, hydrolysis, which I believe is what is happening.
 

darthseres

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I found this ... someone coul explain in detail the reaction ??? first 3 steps I understand ... But for example Why Iodine that take the place of the OH , in last step disappear ???
 

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SoldadoDeDrogas

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The reaction with pseudo and RP/I will work with minimal to no water (according to what I have heard and researched - I have not experienced it for myself)
This is because when the iodine is made into HI as a result of the presence of RP, the pseudo loses a molecule (pseudo is being reduced into meth). So this extra molecule is basically given off as water, or condenses into water? So the reaction is able to sustain itself as it goes. It works in the presence of all the reagents, it wont create this reaction loop with just HI and pseudo or the hypophosphorous routes.

I could be wrong here, so someone correct me. This is just how I think I understand this reaction.
 

l4wl13t

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Is the required iodine the same as the iodine used to detect starch?
 
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