Metamfetamiini süntees efedriinist või pseudoefedriinist

tankikan

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Kuidas on ühe poti meetodiga? See tundub kõige lihtsam viis, kuna meil on vaja lihtsalt segada pseudoefedriini, ammooniumnitraati, eetrit, liitiummetalli, naatriumhüdroksiidi ja veidi vett korraga pudelis ja raputada seda kuni teatud punktini, kus me siis filtreerime ülemise kihi välja ja lõpuks kasutame hcl-happegaasi, et "soolata välja" (nagu video terminites) metamfetamiini. Aga ma ei ole kindel kvaliteedis. Ja võib-olla selle protsessi puuduseks on see, et see võib olla väga ohtlikult ohtlik loksutamise ajal, kuna see hõlmas surmavat vähendamist pudelis. Ma on hakanud tegema nimekirja eespool mainitud punktist, ehk järgmisel nädalal peaksin saama kõik koostisosad. Aga ikka ootan mis tahes nõuandeid, kuna see ei ole minu töövaldkond. Palun parandage mind, kui on mõni puuduv koostisosa.

Vabandust, kuna ma ei kirjuta üksikasjadesse iga sammu kohta. Aga valmis jagama, kui keegi on huvitatud.

Tervitused.
 

waltjr5858

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Empty out a good solid fire extinguisher with threads that let you unscrew the top... empty it clean it and you got a great reaction vessel thats safe and can take pressure. You can let pressure out through the trigger if needed
 
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millised on mõõtmised 5 grammi väärtuses metamfetamiini jaoks
 

PseudoMicroGravity

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Te peate silmas vajalike lähteainete kogust? Ma kasutasin alati 1 - 1 - 1/3 suhet. Nii et kui te tahaksite teha 10 grammi, et oleks lihtsam arvutada, oleks vaja 10 grammi Pseudo, 10 grammi joodi ja 3,3 grammi Red P. Siis teie konkreetse küsimuse puhul oleks vaja 5 grammi Pseudo, 5 grammi Io ja 1,61 grammi Red katalüsaatorit. Kui see on ma tegin selle kiire räpane matemaatika Mt peas õigesti! lol
 

waltjr5858

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What about the amount of water....important especially if they are going for a 24 hour reflux. Too much water dilutes the HI formed and it won't do squat
 

signalbrow

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handle

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AKINCI

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I succeeded in this matter a long time ago, thank you for your interest.
 

@speedboysss

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Why do I only produce this and when it is burned in a pipe it turns black unlike the meth I know
 

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darthseres

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A simple technical/theoretical question... The reaction is an oxidation/reduction... Considering that the main elements are Iodine, Phosphorus and Ephedrine... what exactly is the precise role of each element? Which one is oxidized? Which one is reduced? And the third?... I'm a new student, forgive my ignorance
 

rhinoceros

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Hello

I want to buy pharmaceutcal (Sudafed) and extract ephedrine to make philopon. I don't even know how to extract ephedrine from pharmaceutcal (Sudafed). I would really appreciate it if you could explain it in detail since I'm a beginner. I would like a detailed explanation so that I can get the finished product from the beginning.

I hope you stay healthy and have a great day today.
 

SoldadoDeDrogas

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@darthseres
Ephedrine/Pseudo is being reduced into methamphetamine (Philopon?)
Iodine is oxidized or hydrolyzed into HI, which does the reducing.
Red P is the catalyst.
I'm also not a chemist so I could be wrong.

@rhinoceros All you have to do is spend time looking and studying the forum. It is all here. Many of us have figured it out without any knowledge or experience in a small amount of time with the resources at this site. If you dig in and show that you are trying instead of asking for someone to do it for you, people will try to help if you need it. We're not gonna repeat what is already here..
 

darthseres

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Iodine is Oxidized ? Are you sure ? For what I know Oxidation means that the element lose an electron ... And in this case Iodine forms a polar covalent bond with hydrogen(and iodine is more elctronegative so almost gain an elctrone from Hydrogen) in the formation of HI ...
 

SoldadoDeDrogas

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As I said, I'm not a chemist, so no, I am only guessing.
According to one definition; Oxidation has to do with the addition of oxygen or any electronegative elements or the removal of hydrogen or any electropositive element. I was really leaning more towards the latter, hydrolysis, which I believe is what is happening.
 

darthseres

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I found this ... someone coul explain in detail the reaction ??? first 3 steps I understand ... But for example Why Iodine that take the place of the OH , in last step disappear ???
 

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SoldadoDeDrogas

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The reaction with pseudo and RP/I will work with minimal to no water (according to what I have heard and researched - I have not experienced it for myself)
This is because when the iodine is made into HI as a result of the presence of RP, the pseudo loses a molecule (pseudo is being reduced into meth). So this extra molecule is basically given off as water, or condenses into water? So the reaction is able to sustain itself as it goes. It works in the presence of all the reagents, it wont create this reaction loop with just HI and pseudo or the hypophosphorous routes.

I could be wrong here, so someone correct me. This is just how I think I understand this reaction.
 

l4wl13t

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Is the required iodine the same as the iodine used to detect starch?
 
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