any expert Methylamine

[ass2772]

Hello, a tutorial to do at home for the transformation of methylamine HCL into methylamine 40% aqua?

 

[ass2772]

with homemade equipment

 

[ass2772]

uppp

 

[Frit Buchner]

read this

 

[alpino]

Ingredients:

Methylamine hydrochloride (solid)

Sodium hydroxide (NaOH) or Potassium hydroxide (KOH) (solid)

Water

Instructions:

Prepare Basic Solution:

Dissolve sodium hydroxide (NaOH) or potassium hydroxide (KOH) in water to create a basic solution with a concentration of 20-30%.

Dissolve Methylamine Hydrochloride:

Dissolve the methylamine hydrochloride in water to create a concentrated solution.

Calculate Volumes:

Calculate the volume of the concentrated methylamine hydrochloride solution needed to achieve a 40% methylamine concentration. For example, for 100 mL of 40% methylamine solution, you'll need 40 mL of methylamine.

Mix Solutions:

Slowly add the calculated volume of the concentrated methylamine hydrochloride solution to the basic solution while stirring continuously.

Monitor pH:

Monitor the pH of the solution as you add the base. Continue adding the base until the pH reaches around 10-11.

Separate:

Allow the solution to settle, then decant or siphon off the liquid portion containing the methylamine solution.

Safety Precautions:

Handle chemicals safely in a well-ventilated area.

Wear appropriate protective gear, such as gloves and goggles.

Following these steps should yield a 40% methylamine solution.

 

[alpino]

easier this one

 

[Frit Buchner]

I'm skeptical and I'll tell you why. I previously calculated that the maximum percentage of methylamine that could dissolve in water was 50% w/w. By making a solution of methylammonium chloride and a solution of base, you aren't going to be able to achieve a 40% solution. Keeping in mind you can't concentrate it through distillation or evaporation because the methylamine is a gas at room temperature and volume.
Another insurmountable hurdle is the fact that methylammonium chloride ( methylamine HCL) has A solubility of 1.8g/ LITER! IN 20°C water and CH³NH² has a yeild of 43% ( 100g of CH³NH²HCL produces 43g of
CH³NH ²)

 

[alpino]

I'm skeptical and I'll tell you why. I previously calculated that the maximum percentage of methylamine that could dissolve in water was 50% w/w. By making a solution of methylammonium chloride and a solution of base, you aren't going to be able to achieve a 40% solution. Keeping in mind you can't concentrate it through distillation or evaporation because the methylamine is a gas at room temperature and volume.
Another insurmountable hurdle is the fact that methylammonium chloride ( methylamine HCL) has A solubility of 1.8g/ LITER! IN 20°C water and CH³NH² has a yeild of 43% ( 100g of CH³NH²HCL produces 43g of
CH³NH ²)

Frit Buchnerit seems achieving 40% solution of methylamine trouigh the method involving potassium carbonate is no feasibile. if a 40% solution is requiered, alternative approaches or considerations would be necessary

 

[Frit Buchner]

Oh and 1 more thing. Neutralizing an HCL with a R' Oh produces H²O and R'CL. R' representing anything that will hang on to a CL-. 1 mole of acid + 1 mole of base = 1 mole of salt and 1 mole of water

 

[alpino]

Oh and 1 more thing. Neutralizing an HCL with a R' Oh produces H²O and R'CL. R' representing anything that will hang on to a CL-. 1 mole of acid + 1 mole of base = 1 mole of salt and 1 mole of water

Frit BuchnerYou're correct that neutralizing one mole of acid with one mole of base produces one mole of salt and one mole of water. In this case, the salt formed would indeed be R'Cl, where R' represents the group that attaches to the chloride ion.

 

[alpino]

Oh and 1 more thing. Neutralizing an HCL with a R' Oh produces H²O and R'CL. R' representing anything that will hang on to a CL-. 1 mole of acid + 1 mole of base = 1 mole of salt and 1 mole of water

Frit Buchnerthanks for clarification

 

[jotoy]

Does this way would work for methylamine in methanol solution?