How to dissolve methylamine, are my calculations correct?

[madafaka]

Hello guys,

I have 33 percent methylamine in methylalcohol, according to my calculations i have to add 3.3 liters methanol to have 10 percent methylamine thati can use in reaction.Are my calculations correct?

 

[OrgUnikum]

Nope.

The 33% is w/w this means by weight. If you take 100 g of your 33% solution then this contains 33 g MeNH2 and 67 g MeOH. 33 g would be 10% of 330 g. 330 - 33 = 297. So its 33 g MeNH2 and 297 g MeOH. But you have already 67 g methylalcohol so 297 - 67 = 230. Voila' ! You have to add 230 g alcohol to 100 g 33% methylamine solution to get a 10% solution.

Don't even try to work with ml here or you will get very unhappy as then you would have to include the density of the solution in different strength into the calculation and thats where all fun ends. Just do it by weight and by weight only.

hope this helps

 

[madafaka]

Nope.

The 33% is w/w this means by weight. If you take 100 g of your 33% solution then this contains 33 g MeNH2 and 67 g MeOH. 33 g would be 10% of 330 g. 330 - 33 = 297. So its 33 g MeNH2 and 297 g MeOH. But you have already 67 g methylalcohol so 297 - 67 = 230. Voila' ! You have to add 230 g alcohol to 100 g 33% methylamine solution to get a 10% solution.

Don't even try to work with ml here or you will get very unhappy as then you would have to include the density of the solution in different strength into the calculation and thats where all fun ends. Just do it by weight and by weight only.

hope this helps

OrgUnikumThank you very much sir.

Your post is very helpfull, finally i understand.Thank you very much sir

 

[OrgUnikum]

You are welcome!

No need to "Sir" me though, I appreciate respect but abhor titles.