Solution of amonnia??? Cocaine

[mainkaimpf555]

Hello people, I am trying to extract cocaine. the recipe, a solution of 100ml 10% ammonia. How can this solution be done? I have a 150ml 22% ammonia solution. distilled from caustic soda and urea

 

[Frit Buchner]

Make it 330ml by adding water

 

[TheCook]

In order to dilute 150ml of a 22% ammonia solution to a concentration of 10%, you can use the dilution formula:

• Where:
  
  • C1 is the initial concentration (22%)
  • V1 is the initial volume (150 ml)
  • C2 is the target concentration (10%)
  • V2 is the target volume, which we want to calculate.

First, we calculate the target volume V2 and then subtract V1 from it to find the volume of water to be added.

Rearranging the formula:
V2 = C1 x V1 \ C2

In your case:
V2 = 22% x 150 \ 10% = 330ml

The target volume of the diluted solution is 330 ml. To go from 150 ml of a 22% ammonia solution to 330 ml of a 10% solution, we calculate the amount of water to be added:

V2 - V1 = 330ml - 150ml = 180ml

Thus, you need to add 180 ml of (distilled) water to the original solution to decrease the concentration to 10%.

 

[Frit Buchner]

In order to dilute 150ml of a 22% ammonia solution to a concentration of 10%, you can use the dilution formula:

• Where:
  
  • C1 is the initial concentration (22%)
  • V1 is the initial volume (150 ml)
  • C2 is the target concentration (10%)
  • V2 is the target volume, which we want to calculate.

First, we calculate the target volume V2 and then subtract V1 from it to find the volume of water to be added.

Rearranging the formula:
V2 = C1 x V1 \ C2

In your case:
V2 = 22% x 150 \ 10% = 330ml

The target volume of the diluted solution is 330 ml. To go from 150 ml of a 22% ammonia solution to 330 ml of a 10% solution, we calculate the amount of water to be added:

V2 - V1 = 330ml - 150ml = 180ml

Thus, you need to add 180 ml of (distilled) water to the original solution to decrease the concentration to 10%.

TheCookYeah. I didn't have a statement prepared to say," if you double it you'd have 300ml of 11%, then 300×11÷10=330

 

[Caleb]

Yeah. I didn't have a statement prepared to say," if you double it you'd have 300ml of 11%, then 300×11÷10=330

Frit BuchnerIf TheCook is who I think he is, he is be a better chemist than everyone here. Not even close.

 

[mainkaimpf555]

thanks Bro

 

[Caleb]

thanks Bro

mainkaimpf555still reading fine books from Germany in the twenties?