The theoretical way:
Molar mass Hg: 200.59g
Molar mass HNO3: 63.01g *4 = 252.04g / 1.51g/ml = 166.91ml HNO3 = 278.18ml 60%
20ml 60% = 12ml HNO3 * 1.51g/ml =18.12g HNO3
Needed Hg 14.42g / 13.55g/ml =1,06ml Hg
But normally you weigh your mercury and then you calculate with an excess of acid.
Pennywisehello sir, many thanks to your reply, from you calculation i come out on my own case, please help me out:
I have 68% Nitric Acid 500ML, Mercury 100 g, the density i got from
en.wikipedia.org
en.wikipedia.org
with Hg + 4HNO3, I want to scale down to around 50g Mercury, so can I have (Hg/4) + HNO3 ?
if yes,
solution of HNO3(63.01g / 1.51 g/ml) = (41.73ml / 68%) = 61.37ml
mass of mercury needed, 200.59g / 4 = 50.1475g, because I wanted to have gram instead of ml (possible?)
this seems really really wrong, and I am so embarrassed, please help me out
and your last two lines of the calculation,
20ml 60% = 12ml HNO3 * 1.51g/ml =18.12g HNO3
Needed Hg 14.42g / 13.55g/ml =1,06ml Hg
where are those calculation needed? its HNO3 in ml needed and gram of Hg right?