Syntéza metamfetamínu z P2P redukciou NaBH4. Stredne veľký rozsah.

btcboss2022

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Dobrý deň,

Po mnohých testoch s použitím metylamínu HCL na základe tejto metódy sa s vami podelím o najlepší spôsob, ktorý som našiel na získanie metamfetamínovej frebazy vo veľkom rozsahu:

  • 966 gr P2P
  • 14 litrov metanolu
  • 1183 gr Methylamine HCL
  • 638 gr NaOH
  • 452 gr Bezvodý síran sodný
  • 105 gr NaBH4
  • 35 l destilovanej vody
  • 7 litrov DCM

- Naplňte reaktor 14 l metanolu
- Za miešania rozpustite metylamín HCL
- Nastavte teplotu reaktora na 0 C (nie teplotu zmesi) a pridajte NaOH, teplota sa zvýši
- Keď sa teplota vráti na 20 C, pridajte P2P, teplota sa zvýši a miešajte počas 45 minút až 1 hodiny
- Pridajte 252 g bezvodého síranu sodného
- Keď teplota zmesi dosiahne 8C, začnite po častiach pridávať NaBH4, pričom teplota nesmie prekročiť 20C
- Keď sa pridá všetok NaBH4, nechajte zmes miešať pri teplote 20C počas približne 2 hodín, kým zmes neprestane bublať
- Pridajte vodu a pokračujte v miešaní počas 5 minút
- Pridajte DCM a miešajte počas 10 minút
- Prestaňte miešať a nechajte vrstvy oddeliť
- Ponechajte si spodnú vrstvu a hornú zlikvidujte (nie je výhodné extrahovať túto vodnú fázu)
- Do zachovanej vrstvy pridajte 200 g bezvodého síranu sodného a premiešajte ju
- Prefiltrujte ju v Buchnerovom lieviku
- Odparte DCM
- Získaná čistá a zapáchajúca freebáza metamfetamínu

;-)
 
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snowbones

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Is the 35 litres of water added to ensure seperation of the dcm and water cos of the methanol present to stop it all mixing?
and are you using a 100 litre HDPE paint bucket as the reaction vessel?
 

Chemistry lntern

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Excuse me! Is it necessary to use an ice bath when setting the reaction temperature to 0 degrees (not the temperature of the mixture
 

Atompower

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Has any one trying this method of btc boss and had success with his write up
 

rage565

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Is there a video of this procedure available?
 

G.Patton

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Have you tried to open Video section?
 

Grubby

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Is 15g of NaBH4 enough as the reducing agent for 138g of P2P? Or should I add a small amount of reducing agent to avoid some side reactions?
 

G.Patton

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Hello, yes it's not enough. You have to add at least equimolar amount 38.91g of NaBH4. It's even worth to add a little more, ~1.1 eqviv 42.8g.
 

Grubby

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Idol, there must be a special reason why you choose to use less reducing agent! For example, to avoid certain side reactions or to favor certain steps? Please Master, please enlighten me on the mystery behind this.
 

GnarleyBarley

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You don't need that much, 15 g (maybe a tiny bit more) is enough. 1 mol NaBH4 can reduce more than just 1 mol of imine. It can theoretically reduce 4 moles!!!

Don't know why patton says otherwise, but it's not true. and countless of articles, synthesis on forums and so on pretty much proves it

The following is for MDMA but the same molar ratio of NaBH4 applies to methamphetamine synthesis (here 0.47 equivalents is used)
0xX6LgyRST
 

Chemistry lntern

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How does methylamine hydrochloride and methanol produce a 10% methylamine methanol solution
 

GnarleyBarley

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Methylamine hydrochloride in methanol, add naoh.
You now need to filter the solution (NaCl is precipitated) and dry it with something (sieves, mgso4 etc). Filter it again
or just filter it one time after mgso4

Notice: More products are formed than what is shown in the table below (NaCl) is not shown because I don't care about how many grams of NaCl is produced, it will be filtered of anyway

CH6ClN = Methylamine hydrochloride, CH5N = methylamine, HNaO is NaOH (This table was made automatically in chemdraw, and this is how they do it.
KbwCJYLjef


As you can see, 26g of water is produced to make 45g methylamine from 98g of methylamine hydrochloride. Therefor you need something to dry up all the 26g of water (minimum)

I failed this reaction when I didn't dry it enough (because I didn't realize that so much water was actually produced (just added a little bit of mgso4 and thought I was good to go)

Also you don't need to have exactly 10% Methanol solution. Just enough to hold all the methylamine and enough to keep dilute the reaction enough.
 

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