Obidva preklady fungujú a obidva sú dobré.
Syntéza 4-MMC (mefedrónu). Kompletný videonávod.
C10H11BrO + CH5N → C11H15NO + HBr
Ako vidieť z rovnice, z jednej molekuly 2-bróm-4-metylpropiofenónu vzniká jedna molekula mefedrónu.
C10H11BrO : 227,0977 g/mol
C11H15NO : 177,2429 g/mol
227.0977/177.2429=1.28127953
Koeficient je 1,28127953
To znamená, že zo 100 g 2-bróm-4-propiofenónu získate 78,0469818 g mefedrónovej bázy.
Hmotnosť mefedrónhydrochloridu sa zvýši o 1,19 g/cm3 a koeficient bude 1,27273446.
C11H15NO+HCl=177.2429+1.19=178.4329
227.0977/178.4329=1.27273446
100g(C10H11BrO)/1.27273446=78.5709849g(C11H15NO)
Teoretický výťažok reakcie 2-bróm-4-metylpropiofenónu bol 78,5709849 g mefedrónhydrochloridu. Treba však vziať do úvahy, že je ťažké dosiahnuť teoretický výťažok, zvyčajne je strata 20 %.
Ako vidieť z rovnice, z jednej molekuly 2-bróm-4-metylpropiofenónu vzniká jedna molekula mefedrónu.
C10H11BrO : 227,0977 g/mol
C11H15NO : 177,2429 g/mol
227.0977/177.2429=1.28127953
Koeficient je 1,28127953
To znamená, že zo 100 g 2-bróm-4-propiofenónu získate 78,0469818 g mefedrónovej bázy.
Hmotnosť mefedrónhydrochloridu sa zvýši o 1,19 g/cm3 a koeficient bude 1,27273446.
C11H15NO+HCl=177.2429+1.19=178.4329
227.0977/178.4329=1.27273446
100g(C10H11BrO)/1.27273446=78.5709849g(C11H15NO)
Teoretický výťažok reakcie 2-bróm-4-metylpropiofenónu bol 78,5709849 g mefedrónhydrochloridu. Treba však vziať do úvahy, že je ťažké dosiahnuť teoretický výťažok, zvyčajne je strata 20 %.
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Nie sú kvalitne prečistené alebo je málo času na reakciu. Je potrebné uviesť viac podrobností.
- By whitelabel
Greetings
4mp to 4mmc successfully this way for me but starting 4mp was yellow so bromination done as per process.
Resultant mephedrone was a pasty powder and not crystal like salt as in video. Power was also low even after crystallization. Any thoughts on the pasty powder and low power. Yield was about 120 gms recrystallized from 400 ml 4mp.
Is there any way to purify the 4mp we get to start with or is that fine?
Would a superior product be possible if 4mp is brominated using NBs and PTSA, purified with a solvent nd then make the nmp synthesis from that 2b4m?
Thanks in advance. Tc
4mp to 4mmc successfully this way for me but starting 4mp was yellow so bromination done as per process.
Resultant mephedrone was a pasty powder and not crystal like salt as in video. Power was also low even after crystallization. Any thoughts on the pasty powder and low power. Yield was about 120 gms recrystallized from 400 ml 4mp.
Is there any way to purify the 4mp we get to start with or is that fine?
Would a superior product be possible if 4mp is brominated using NBs and PTSA, purified with a solvent nd then make the nmp synthesis from that 2b4m?
Thanks in advance. Tc
Nepridával som acetón, len voľnú bázu MMC v benzéne, a nakvapkal som 30 % HCl pri pH 5,5. Kyselinu som pridával pomaly. Mohol by byť problém v acetóne? Zabudol som, pretože zvyčajne okysľujem pomocou DCM+voda, takže acetón mi neprišiel na um. Ako ste okyslili tú krásku na obrázku? Ďakujem veľmi pekne.
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- By William D.
Ak používate aq. kyselinu chlorovodíkovú, potrebujete rozpúšťadlo, ktoré viaže vodu. Je to acetón alebo alkohol (etanol, propanol)
Dobrý deň, priatelia, kde môžem nájsť NMP?
This method can use 1451-82-7?
Of course you can, in which case you skip the first bromination step and proceed to the methylamination step.
@Marvin "Popcorn" Sutton can we scale this up using a 50litre batch reactor and drop the bromine Benzene mix from the reactors dropping funnel without any issues?
Bromine mix in an enclosed dropping funnel is a litle scary
Bromine mix in an enclosed dropping funnel is a litle scary