Begge dele fungerer, og begge dele er godt.
Syntese af 4-MMC (mephedron). Komplet videovejledning.
C10H11BrO + CH5N → C11H15NO + HBr
Som det fremgår af ligningen, producerer et molekyle 2-brom-4-methylpropiophenon et molekyle mephedron.
C10H11BrO : 227,0977 g/mol
C11H15NO : 177,2429 g/mol
227.0977/177.2429=1.28127953
Koefficienten er 1.28127953
Det betyder, at fra 100 g 2-brom-4-propiophenon får du 78,0469818 g mephedronbase.
Massen af mephedronhydrochlorid vil stige med 1,19 g/cm3, og koefficienten vil være 1,27273446
C11H15NO+HCl=177.2429+1.19=178.4329
227.0977/178.4329=1.27273446
100g(C10H11BrO)/1.27273446=78.5709849g(C11H15NO)
Det teoretiske udbytte af reaktionen af 2-brom-4-methylpropiophenon var 78,5709849 g mephedronhydrochlorid. Men det bør overvejes, at det er vanskeligt at opnå det teoretiske udbytte, normalt er tabet 20 %.
Som det fremgår af ligningen, producerer et molekyle 2-brom-4-methylpropiophenon et molekyle mephedron.
C10H11BrO : 227,0977 g/mol
C11H15NO : 177,2429 g/mol
227.0977/177.2429=1.28127953
Koefficienten er 1.28127953
Det betyder, at fra 100 g 2-brom-4-propiophenon får du 78,0469818 g mephedronbase.
Massen af mephedronhydrochlorid vil stige med 1,19 g/cm3, og koefficienten vil være 1,27273446
C11H15NO+HCl=177.2429+1.19=178.4329
227.0977/178.4329=1.27273446
100g(C10H11BrO)/1.27273446=78.5709849g(C11H15NO)
Det teoretiske udbytte af reaktionen af 2-brom-4-methylpropiophenon var 78,5709849 g mephedronhydrochlorid. Men det bør overvejes, at det er vanskeligt at opnå det teoretiske udbytte, normalt er tabet 20 %.
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Jeg har fundet en leverandør af 2-Bromo-4-Methylpropiophenone væske, men jeg ved ikke, hvordan jeg skal starte fra dette punkt, og hvor meget væske skal jeg bruge til at lave 100 g 4mmc.jeg har brug for nogle råd.
Ikke kvalitativt oprenset eller for lidt tid til reaktionen. Der er brug for flere detaljer.
- By whitelabel
Greetings
4mp to 4mmc successfully this way for me but starting 4mp was yellow so bromination done as per process.
Resultant mephedrone was a pasty powder and not crystal like salt as in video. Power was also low even after crystallization. Any thoughts on the pasty powder and low power. Yield was about 120 gms recrystallized from 400 ml 4mp.
Is there any way to purify the 4mp we get to start with or is that fine?
Would a superior product be possible if 4mp is brominated using NBs and PTSA, purified with a solvent nd then make the nmp synthesis from that 2b4m?
Thanks in advance. Tc
4mp to 4mmc successfully this way for me but starting 4mp was yellow so bromination done as per process.
Resultant mephedrone was a pasty powder and not crystal like salt as in video. Power was also low even after crystallization. Any thoughts on the pasty powder and low power. Yield was about 120 gms recrystallized from 400 ml 4mp.
Is there any way to purify the 4mp we get to start with or is that fine?
Would a superior product be possible if 4mp is brominated using NBs and PTSA, purified with a solvent nd then make the nmp synthesis from that 2b4m?
Thanks in advance. Tc
Jeg tilsatte ikke acetone, kun MMC freebase i benzen, og jeg dryppede 30 % HCl ved pH 5,5 i. Jeg tilsatte syren langsomt. Kan acetone være problemet? Jeg glemte det, fordi jeg normalt syrner med DCM+vand, så jeg tænkte ikke på acetone. Hvordan syrnede du skønheden på billedet? Tusind tak skal du have.
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- By William D.
Hvis du bruger aq. saltsyre, skal du bruge et opløsningsmiddel, der binder vand. Det er acetone eller alkohol (ethanol, propanol).
Hej venner, hvor kan jeg finde NMP?
This method can use 1451-82-7?
Of course you can, in which case you skip the first bromination step and proceed to the methylamination step.
@Marvin "Popcorn" Sutton can we scale this up using a 50litre batch reactor and drop the bromine Benzene mix from the reactors dropping funnel without any issues?
Bromine mix in an enclosed dropping funnel is a litle scary
Bromine mix in an enclosed dropping funnel is a litle scary