Metamfetaminsyntese fra P2P ved NaBH4-reduktion. Mellemstor skala.

btcboss2022

Don't buy from me
Resident
Joined
Mar 15, 2022
Messages
650
Solutions
1
Reaction score
677
Points
93
Deals
8
Hej med dig,

Efter mange forsøg med Methylamine HCL baseret på denne metode vil jeg dele den bedste måde, jeg har fundet til at få Methamphetamine freebase i stor skala:

  • 966 gr P2P
  • 14 liter methanol
  • 1183 gr Methylamin HCL
  • 638 g NaOH
  • 452 gr Vandfrit natriumsulfat
  • 105 gr NaBH4
  • 35 L destilleret vand
  • 7 liter DCM

- Fyld reaktoren med 14 L methanol
- Opløs metylamin HCL under omrøring
- Sæt reaktortemperaturen på 0C (ikke blandingstemperaturen) og tilsæt NaOH, temperaturen vil stige
- Når temperaturen er kommet tilbage til 20C, tilsættes P2P, og temperaturen vil stige under omrøring i 45 minutter-1 time.
- Tilsæt 252 g vandfrit natriumsulfat
- Når blandingens temperatur når op på 8C, begynder du at tilsætte NaBH4 portionsvis, uden at overstige 20C.
- Når al NaBH4 er tilsat, lad det blande under 20C i ca. 2 timer, indtil blandingen holder op med at boble
- Tilsæt vand og fortsæt med at blande i 5 minutter
- Tilsæt DCM og bland i 10 minutter
- Stop omrøring og lad lagene blive adskilt
- Behold det nederste lag og kassér det øverste (det er ikke rentabelt at ekstrahere denne vandige fase)
- Tilsæt 200 g vandfrit natriumsulfat til det gemte lag og bland det
- Filtrer det i Buchner-tragt
- Inddamp DCM'en
- Ren og ildelugtende metamfetamin freebase opnået

;-)
 
View previous replies…

snowbones

Don't buy from me
Member
Language
🇺🇸
Joined
Aug 31, 2022
Messages
2
Reaction score
0
Points
1
Is the 35 litres of water added to ensure seperation of the dcm and water cos of the methanol present to stop it all mixing?
and are you using a 100 litre HDPE paint bucket as the reaction vessel?
 

Chemistry lntern

Don't buy from me
Member
Language
🇺🇸
Joined
Dec 9, 2024
Messages
16
Reaction score
0
Points
1
Excuse me! Is it necessary to use an ice bath when setting the reaction temperature to 0 degrees (not the temperature of the mixture
 

Atompower

Don't buy from me
Member
Language
🇬🇧
Joined
Oct 18, 2024
Messages
3
Reaction score
0
Points
1
Has any one trying this method of btc boss and had success with his write up
 

rage565

Don't buy from me
New Member
Language
🇺🇸
Joined
Mar 2, 2025
Messages
1
Reaction score
0
Points
1
Is there a video of this procedure available?
 

G.Patton

Expert
Joined
Jul 5, 2021
Messages
2,965
Solutions
3
Reaction score
3,339
Points
113
Deals
1
Have you tried to open Video section?
 

Grubby

Don't buy from me
Resident
Language
🇺🇸
Joined
Jul 27, 2024
Messages
38
Reaction score
18
Points
8
Is 15g of NaBH4 enough as the reducing agent for 138g of P2P? Or should I add a small amount of reducing agent to avoid some side reactions?
 

G.Patton

Expert
Joined
Jul 5, 2021
Messages
2,965
Solutions
3
Reaction score
3,339
Points
113
Deals
1
Hello, yes it's not enough. You have to add at least equimolar amount 38.91g of NaBH4. It's even worth to add a little more, ~1.1 eqviv 42.8g.
 

Grubby

Don't buy from me
Resident
Language
🇺🇸
Joined
Jul 27, 2024
Messages
38
Reaction score
18
Points
8
Idol, there must be a special reason why you choose to use less reducing agent! For example, to avoid certain side reactions or to favor certain steps? Please Master, please enlighten me on the mystery behind this.
 

GnarleyBarley

Don't buy from me
Resident
Language
🇺🇸
Joined
Dec 23, 2024
Messages
24
Reaction score
5
Points
3
You don't need that much, 15 g (maybe a tiny bit more) is enough. 1 mol NaBH4 can reduce more than just 1 mol of imine. It can theoretically reduce 4 moles!!!

Don't know why patton says otherwise, but it's not true. and countless of articles, synthesis on forums and so on pretty much proves it

The following is for MDMA but the same molar ratio of NaBH4 applies to methamphetamine synthesis (here 0.47 equivalents is used)
0xX6LgyRST
 

Chemistry lntern

Don't buy from me
Member
Language
🇺🇸
Joined
Dec 9, 2024
Messages
16
Reaction score
0
Points
1
How does methylamine hydrochloride and methanol produce a 10% methylamine methanol solution
 

GnarleyBarley

Don't buy from me
Resident
Language
🇺🇸
Joined
Dec 23, 2024
Messages
24
Reaction score
5
Points
3
Methylamine hydrochloride in methanol, add naoh.
You now need to filter the solution (NaCl is precipitated) and dry it with something (sieves, mgso4 etc). Filter it again
or just filter it one time after mgso4

Notice: More products are formed than what is shown in the table below (NaCl) is not shown because I don't care about how many grams of NaCl is produced, it will be filtered of anyway

CH6ClN = Methylamine hydrochloride, CH5N = methylamine, HNaO is NaOH (This table was made automatically in chemdraw, and this is how they do it.
KbwCJYLjef


As you can see, 26g of water is produced to make 45g methylamine from 98g of methylamine hydrochloride. Therefor you need something to dry up all the 26g of water (minimum)

I failed this reaction when I didn't dry it enough (because I didn't realize that so much water was actually produced (just added a little bit of mgso4 and thought I was good to go)

Also you don't need to have exactly 10% Methanol solution. Just enough to hold all the methylamine and enough to keep dilute the reaction enough.
 

Attachments

  • cE34I0O9Fh.png
    cE34I0O9Fh.png
    14.5 KB · Views: 2
Top