4-MMC (mephedrone) synthesis. Complete video tutorial.

Joined
Jul 25, 2021
Messages
202
Reaction score
299
Points
63
C10H11BrO + CH5N → C11H15NO + HBr
As can be seen from the equation, one molecule of 2-bromo-4-methylpropiophenone produces one molecule of mephedrone.
C10H11BrO : 227.0977 g/mol
C11H15NO : 177.2429 g/mol
227.0977/177.2429=1.28127953
The coefficient is 1.28127953
This means that from 100g of 2-bromo-4-propiophenone, you will get 78.0469818g of mephedrone base.

The mass of mephedrone hydrochloride will increase by 1.19 g/cm3 and the coefficient will be 1.27273446
C11H15NO+HCl=177.2429+1.19=178.4329
227.0977/178.4329=1.27273446

100g(C10H11BrO)/1.27273446=78.5709849g(C11H15NO)
The theoretical yield of the reaction of 2-bromo-4-methylpropiophenone was 78.5709849g mephedrone hydrochloride. But it should be considered that it is difficult to achieve the theoretical yield, usually the loss is 20%.
 
Last edited by a moderator:

Bazooka90

Don't buy from me
Resident
Language
🇺🇸
Joined
May 8, 2022
Messages
41
Reaction score
3
Points
8
I have found a supplier of 2-Bromo-4-Methylpropiophenone liquid but i dont know how to start from this point and how much liquid should i use to make 100g of 4mmc.I need some advices.
 

Nsowonxmd

Don't buy from me
Resident
Language
🇨🇿
Joined
Sep 12, 2024
Messages
9
Reaction score
7
Points
3
To bych. I didn't. In a liquid. Good. Peppercorn
 

Tsigger

Don't buy from me
Member
Language
🇭🇺
Joined
Jan 16, 2024
Messages
4
Reaction score
3
Points
3
I didn’t add acetone, just MMC freebase in benzene, and I dripped in 30% HCl at pH 5.5. I added the acid slowly. Could acetone be the issue? I forgot, because I usually acidify with DCM+water, so acetone didn’t come to mind. How did you acidify the beauty in the picture? Thank you very much.
 
View previous replies…

goatlabs666

Don't buy from me
Resident
Language
🇪🇸
Joined
Jun 17, 2024
Messages
5
Reaction score
1
Points
3
Deals
3
Thanks bro
 
Top